Optimal. Leaf size=339 \[ \frac{4 \sqrt{2} d^{7/4} ((a+b x) (c+d x))^{3/4} \sqrt{(a d+b c+2 b d x)^2} \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right ) \sqrt{\frac{(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt{b c-a d}}\right ),\frac{1}{2}\right )}{7 \sqrt [4]{b} (a+b x)^{3/4} (c+d x)^{3/4} (b c-a d)^{3/2} (a d+b c+2 b d x) \sqrt{(a d+b (c+2 d x))^2}}+\frac{8 d \sqrt [4]{c+d x}}{7 (a+b x)^{3/4} (b c-a d)^2}-\frac{4 \sqrt [4]{c+d x}}{7 (a+b x)^{7/4} (b c-a d)} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.279612, antiderivative size = 339, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.21, Rules used = {51, 62, 623, 220} \[ \frac{4 \sqrt{2} d^{7/4} ((a+b x) (c+d x))^{3/4} \sqrt{(a d+b c+2 b d x)^2} \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right ) \sqrt{\frac{(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}+1\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt{b c-a d}}\right )|\frac{1}{2}\right )}{7 \sqrt [4]{b} (a+b x)^{3/4} (c+d x)^{3/4} (b c-a d)^{3/2} (a d+b c+2 b d x) \sqrt{(a d+b (c+2 d x))^2}}+\frac{8 d \sqrt [4]{c+d x}}{7 (a+b x)^{3/4} (b c-a d)^2}-\frac{4 \sqrt [4]{c+d x}}{7 (a+b x)^{7/4} (b c-a d)} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 51
Rule 62
Rule 623
Rule 220
Rubi steps
\begin{align*} \int \frac{1}{(a+b x)^{11/4} (c+d x)^{3/4}} \, dx &=-\frac{4 \sqrt [4]{c+d x}}{7 (b c-a d) (a+b x)^{7/4}}-\frac{(6 d) \int \frac{1}{(a+b x)^{7/4} (c+d x)^{3/4}} \, dx}{7 (b c-a d)}\\ &=-\frac{4 \sqrt [4]{c+d x}}{7 (b c-a d) (a+b x)^{7/4}}+\frac{8 d \sqrt [4]{c+d x}}{7 (b c-a d)^2 (a+b x)^{3/4}}+\frac{\left (4 d^2\right ) \int \frac{1}{(a+b x)^{3/4} (c+d x)^{3/4}} \, dx}{7 (b c-a d)^2}\\ &=-\frac{4 \sqrt [4]{c+d x}}{7 (b c-a d) (a+b x)^{7/4}}+\frac{8 d \sqrt [4]{c+d x}}{7 (b c-a d)^2 (a+b x)^{3/4}}+\frac{\left (4 d^2 ((a+b x) (c+d x))^{3/4}\right ) \int \frac{1}{\left (a c+(b c+a d) x+b d x^2\right )^{3/4}} \, dx}{7 (b c-a d)^2 (a+b x)^{3/4} (c+d x)^{3/4}}\\ &=-\frac{4 \sqrt [4]{c+d x}}{7 (b c-a d) (a+b x)^{7/4}}+\frac{8 d \sqrt [4]{c+d x}}{7 (b c-a d)^2 (a+b x)^{3/4}}+\frac{\left (16 d^2 ((a+b x) (c+d x))^{3/4} \sqrt{(b c+a d+2 b d x)^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-4 a b c d+(b c+a d)^2+4 b d x^4}} \, dx,x,\sqrt [4]{(a+b x) (c+d x)}\right )}{7 (b c-a d)^2 (a+b x)^{3/4} (c+d x)^{3/4} (b c+a d+2 b d x)}\\ &=-\frac{4 \sqrt [4]{c+d x}}{7 (b c-a d) (a+b x)^{7/4}}+\frac{8 d \sqrt [4]{c+d x}}{7 (b c-a d)^2 (a+b x)^{3/4}}+\frac{4 \sqrt{2} d^{7/4} ((a+b x) (c+d x))^{3/4} \sqrt{(b c+a d+2 b d x)^2} \left (1+\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}\right ) \sqrt{\frac{(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (1+\frac{2 \sqrt{b} \sqrt{d} \sqrt{(a+b x) (c+d x)}}{b c-a d}\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt{b c-a d}}\right )|\frac{1}{2}\right )}{7 \sqrt [4]{b} (b c-a d)^{3/2} (a+b x)^{3/4} (c+d x)^{3/4} (b c+a d+2 b d x) \sqrt{(a d+b (c+2 d x))^2}}\\ \end{align*}
Mathematica [C] time = 0.0250698, size = 73, normalized size = 0.22 \[ -\frac{4 \left (\frac{b (c+d x)}{b c-a d}\right )^{3/4} \, _2F_1\left (-\frac{7}{4},\frac{3}{4};-\frac{3}{4};\frac{d (a+b x)}{a d-b c}\right )}{7 b (a+b x)^{7/4} (c+d x)^{3/4}} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.038, size = 0, normalized size = 0. \begin{align*} \int{ \left ( bx+a \right ) ^{-{\frac{11}{4}}} \left ( dx+c \right ) ^{-{\frac{3}{4}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x + a\right )}^{\frac{11}{4}}{\left (d x + c\right )}^{\frac{3}{4}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b x + a\right )}^{\frac{1}{4}}{\left (d x + c\right )}^{\frac{1}{4}}}{b^{3} d x^{4} + a^{3} c +{\left (b^{3} c + 3 \, a b^{2} d\right )} x^{3} + 3 \,{\left (a b^{2} c + a^{2} b d\right )} x^{2} +{\left (3 \, a^{2} b c + a^{3} d\right )} x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]